Etext 8.46

8.46-A random sample of 10 miniature tootsie rolls was taken from a bag. Each piece was weighed on a actually look at scale. The results in grams were: 3.087, 3.131, 3.241, 3.270, 3.353, 3.400, 3.411, 3.437, 3.477 (a) Construct a 90% sanction time interval for the true mean weight. Sample mean = 3.3048 Sample unoriginal deviation = 0.13199 Standard error: 1.645*0.13199/Sqrt(10) = 0.06866 90% CI- 3.3048-0.06866 < u < 3.3048 + 0.06866 90% CI- 3.23614 < u < 3.37346 (b) What sample size would be necessary to count the true weight with an error rate of +/- 0.03 grams with 90% government agency? n = [1.645*0.13199/0.03]^2 = 7.42^2 = 52.38 Rounding up to twinge for n = 53 (c) Discuss the factors which might cause variate in the weight of the tootsie rolls during manufacturing. Factors such as the amount of ingredients utilize to pick out the tootsie rolls along with the humidity and temperature control. Also the tool tolerances may be a factor in ca using variation during manufacturing. 8.

62- In 1992, the FAA conducted 86,991 pre-employment drug tests on the job applicants who were to be engaged in safety and security related jobs, and institute that 1,143 were absolute. (a) Construct a 95% confidence interval for the existence proportion of positive drug tests. p-hat = 1143/86991 = 0.013139... E = 1.96*sqrt[(0.013139)*(0.98686)/86991] = 0.002393 CI is (0.013139 0.002393, 0.013139 + 0.00239) (b) why is the normality speculation not a line of work, despite the very small care for of p? The normality hypothesis was not a problem because the random samp le was very large.If you want to get a full ! essay, order it on our website: OrderCustomPaper.com

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