Assuming that the distribution Essay

1. Assuming that the distribution is normal for weight relative to the sample and 99% of the male participants scored surrounded by (53.68, 64.64), where did 95% of the values for weight relative to the ideal lie? rophy your resoluteness to two denary places. x=5.48, SD=22.935.48+1.96(22.93) = 170.59925.48-1.96(22.93)=80.7136(80.71,170.60)2. Which of the following(a) values from Table 1 tells us about variability of the lots in a distribution? c. 22.573. Assuming that the distribution for General wellness Perceptions is normal, 95% of the females slews virtually the cockeyed were between what values? cadence your answer to two ten-fold places. x=39.71, SD=25.4639.71+1.96(25.46) = 89.611639.71-1.96(25.46) = -10.1916(-10.19, 89.61)4. Assuming that the distribution of hemorrhoid for Pain is normal, 95% of the mens scores around the mean were between what two values? round off your answer to two decimal places. x=52.53, SD=30.9052.53+1.96(30.90) = 113.09452.53-1.96(30.90) = -8.034(-8.03, 113.09)5. Were the body look scores significantly different for women versus men? Provide a rationale for your answer. Yes, body image scores were significantly higher for women (73.1 17.0) than men (60.2 17.0).6. Assuming that the distribution of Mental Health scores for men is normal, where are 99% of the mens mental wellness scores around the mean in this distribution? Round your answer to two decimal places. x= 57.09, SD=23.7257.09+2.58(23.72)= 118.287657.09-2.58(23.72)= -4.1076(-4.11, 118.29)7. Assuming that the distribution of scores for somatogenetic Functioning in women is normal, where are 99% of the womens scores around the mean in this distribution? Round your answer to two decimal places. X= 65.20, SD=29.79 65.20+2.58(29.79) = 142.058265.20-2.58(29.79) = -11.6582(-11.66, 142.06)8. Assuming that the distribution of scores is normal, 99% of HIV-positive body image scores around the mean were between what two values? Round your answer to two decimal pla ces. Body image scores for manful x= 60.22, SD=16.98 egg-producing(prenominal) x= 73.07, SD= 16.93 Male 60.22+2.58(16.98)= 104.028460.22-2.58(16.98)= 16.4116Female 73.07+2.58(16.93)= 116.749473.07-2.58(16.93)= 29.3906Male and Female HIV+ Body Image scores combined are between (16.41, 116.75)9. Assuming that the distribution of scores for Role Functioning is normal, 99% of the mens scores around the mean were between what values? Round your answer to two decimal places. x=50.00, SD=46.2950.00+2.58(46.29)= 169.428250.00-2.58(46.29)=-69.4282(-69.43,169.43)